Complete question :
The lifespans of gorillas in a particular zoo are normally distributed. The average gorilla lives 20.8 years; the
standard deviation is 3.1 years.
Use the empirical rule (68 – 95 - 99.7%) to estimate the probability of a gorilla living less than 23.9 years.
Answer:
84%
Step-by-step explanation:
Given :
Mean, m = 20.8
Standard deviation, s = 3.1 ; x = 23.9
The Zscore = (x - mean) / standard deviation
P(x < 23.9) = (23.9 - 20.8) / 3.1 = 1
P(x < 23.9) = 1
P(Z < 1) = 0.84134
0.84134 * 100% = 84.13%
= 84%
