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___Li + ___AlPO4 --> ___Al + ___Li3PO4

If 2.3 moles of Aluminum Phosphate are reacted, how many grams of Lithium Phosphate are produced?

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Answer:

266.3 g

Explanation:

  • __Li + __AlPO₄ → __Al + __Li₃PO₄

The balanced reaction is:

  • 3Li + AlPO₄ → Al + Li₃PO₄

First we convert 2.3 moles of AlPO₄ to moles of Li₃PO₄, using the stoichiometric coefficients:

  • 2.3 mol AlPO₄ * [tex]\frac{1molLi_3PO_4}{1molAlPO_4}[/tex] = 2.3 mol Li₃PO₄

Then we convert Li₃PO₄ moles into grams, using its molar mass:

  • 2.3 mol Li₃PO₄ * 115.79 g/mol = 266.3 g

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