Answer:
77.12°
Step-by-step explanation:
Given that:
In triangle OPQ
∠P=70°
line q = 83 inches
line p = 80 inches
To find ∠Q; we use the since rule:
[tex]\dfrac{Sin \ Q}{q} = \dfrac{Sin \ P}{p}[/tex]
[tex]\dfrac{Sin \ Q}{83} = \dfrac{Sin \ 70}{80}[/tex]
[tex]Sin \ Q= \dfrac{Sin \ 70 \times 83}{80}[/tex]
[tex]\text{Sin \ Q= 0.9749}[/tex]
[tex]Q=Sin ^{-1}( 0.9749)[/tex]
[tex]\mathbf{Q = 77.12^0}[/tex]
