Answer:
C. [tex]3j^{3}l[/tex]
Step-by-step explanation:
1) First you cancel [tex]k^{2}[/tex] because they are completely the same. then you take out the constants and simply.
2)You then have to use the Quotient Rule:
[tex]\frac{x^{a} }{x^{b} } =x^{a - b}[/tex]
You should have ...
[tex]3j^{6-3} l^{5-4}[/tex]
3) Simplify 6 − 3 to 3.
[tex]3j^{3} l^{1}[/tex]
4) Simplify 5 − 4 to 1.
5) Use Rule of One: [tex]x^{1} =x[/tex]
Answer is !!!
[tex]3j^{3} l[/tex]
