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Find the perimeter of a rectangle with a width of 2x^2+4x-8 and a length of 3x+8.

A.2x^2+7x

B.4x^2+14x

C.4x^2+14x+32

C.18x^2

Respuesta :

mariazahra22

Answer:

B . 4x^2 + 14x

Step-by-step explanation:

2(2x^2+4x-8) + 2(3x+8)

=4x^2 +8x-16+6x+16

=4x^2+14 (ans)

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