Answer:
[tex] \boxed{h = 5 \sqrt{5}}[/tex]
Step-by-step explanation:
[tex] {h}^{2} = {(2 \sqrt{13} )}^{2} + {( \sqrt{73} )}^{2} \\ {h}^{2} = 4(13) + 73 \\ {h}^{2} = 125 \\ h = \sqrt{125} \\ h = 5 \sqrt{5} [/tex]
