jazroegner jazroegner
  • 23-02-2021
  • Mathematics
contestada

can any one help me on this? this is on my math test due at 11:59.

can any one help me on this this is on my math test due at 1159 class=

Respuesta :

imawolf
imawolf imawolf
  • 23-02-2021

Answer:

[tex]\sqrt{53.19}[/tex] or 7.29

good luck, hope this helps :)

Answer Link
yamunasasidharan0808
yamunasasidharan0808 yamunasasidharan0808
  • 23-02-2021

Answer:

x = 7.3 (approx.)

Step-by-step explanation:

As the given triangle is right angled, we can use Pythagoras theorem.

Hypotenuse = 11.2

Perpendicular = 8.5

Base = ?

To find base :

[tex]Base^{2} = Hypotenuse^{2} - Perpendicular^{2} \\Base^{2} = (11.2)^{2} - (8.5)^{2} \\Base^{2} = 125.44 - 72.25\\Base^{2} = 53.19\\Base = \sqrt{53.19} \\Base = 7.293[/tex]

Thus x = 7.3 (approx.)

Hope it helps.

Answer Link

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