Respuesta :

Answer:

a)B)9π

b)G)16π in²

Step-by-step explanation:

according to the question

[tex]64 \times \frac{\pi}{4} [/tex]

[tex]16\pi \: {in}^{2} [/tex]

as we know

C/d=π

C=dπ

Therefore

C=9π