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23-10-2016
Mathematics

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How do you solve 3log_3 4a=3?

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Аноним Аноним

23-10-2016

3 log₃ 4a=3

1)a(log_b c)=log_b c^a
log₃(4a)³=3

2) log_a x=n ⇔ a^n=x
log₃ (4a)³=3 ⇔ 3³=(4a)³
27=64a³
a³=27/64
a=∛(27/64)
a=3/4

Answer: a=3/4

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