miyuuieeryuuu
miyuuieeryuuu miyuuieeryuuu
  • 23-12-2020
  • Mathematics
contestada

sin^2a-sin^2b=cos^2b-cos^2a​

Respuesta :

jimrgrant1 jimrgrant1
  • 23-12-2020

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

sin²x + cos²x = 1 , then sin²x = 1 - cos²x

Consider the left side

sin²a - sin²b

= (1 - cos²a) - (1 - cos²b)

= 1 - cos²a - 1 + cos²b

= cos²b - cos²a

= right side , thus verified

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