Answer:
x = 4 and y = 1/2
Step-by-step explanation:
Given equations are :
[tex]\dfrac{x}{2}+2y=3\ .....(1)\\\\6y+1=x\ ......(2)[/tex]
Put the value of x from equation (2) in equation (1).
[tex]\dfrac{6y+1}{2}+2y=3\\\\\dfrac{6y+1+4y}{2}=3\\\\\dfrac{10y+1}{2}=3\\\\10y+1=6\\\\10y=5\\\\y=\dfrac{1}{2}[/tex]
Put the value of y in equation (2) :
[tex]6\times \dfrac{1}{2}+1=x\\\\3+1=x\\\\x=4[/tex]
So, the value of x = 4 and y = 1/2.
