Hi there.
The answer is f(0) = 3.
Explanation:
Given 2 functions with given domains.
[tex]f(x) = 5x - 1[/tex]
where x < -2
[tex]f(x) = x + 3[/tex]
where x >= -2
Evaluate the value of f(x) when x = 0. Therefore, f(x)= 5x-1 cannot be used as the given x = 0 is greater than its domain.
Thus, our main function is f(x) = x+3
Evaluate the value by substituting x = 0 in the function.
[tex]f(0) = 0 + 3 \\ f(0) = 3[/tex]
Thus, the answer is f(0) = 3
