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  • 22-11-2020
  • Mathematics
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How do you do this question?

How do you do this question class=

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MathPhys
MathPhys MathPhys
  • 22-11-2020

Answer:

(a) y = ¼ sin(x² + C)

(b) y = ¼ sin(x²)

Step-by-step explanation:

(a) dy/dx = ½ x √(1 − 16y²)

dy / √(1 − 16y²) = ½ x dx

4 dy / √(1 − 16y²) = 2x dx

sin⁻¹(4y) = x² + C

4y = sin(x² + C)

y = ¼ sin(x² + C)

(b) When x=0, y=0.

0 = ¼ sin(C)

C = 0

y = ¼ sin(x²)

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