Answer:
For, this question,
The balanced equation is; 2Al + 3 ----> 2Al
We can now, calculate how many grams of will be needed to completely convert 15 g of Al into Al.
Here, the reaction produces, 2 moles of Al
So, For 15.0 g of Al; we can calculate;
(15.0 g Al) X (1 mole Al / 26.98 g Al) X (3 moles / 2 moles Al) X (159.81 g / 1 mole )
= 133 g of will be needed.
Therefore, 133g of will be needed to completely convert 15 g of Al into Al.
Explanation:
