monicatx0810
monicatx0810 monicatx0810
  • 21-10-2020
  • Mathematics
contestada

A line passes through the point. (4, -7) and has a slope of 5/2
Write an equation in slope-intercept form for this line.​

Respuesta :

hnori22003
hnori22003 hnori22003
  • 21-10-2020

t p = through point

s = slope

[tex]y - y(t \: p) = (s) \times ( \: x - x(t \: p) \: ) \\ [/tex]

[tex]y - ( - 7) = \frac{5}{2} \times (x - 4) \\ [/tex]

[tex]y + 7 = \frac{5}{2} \times (x - 4) \\ [/tex]

[tex]y + 7 = \frac{5}{2}x - \frac{5 \times 4}{2} \\ [/tex]

[tex]y +7 = \frac{5}{2}x - \frac{20}{2} \\ [/tex]

Subtract both sides -7

[tex]y = \frac{5}{2}x - 10 - 7 \\ [/tex]

[tex]y = \frac{5}{2}x - 17 \\ [/tex]

And we're done....

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