kodwjpihaefugdfy kodwjpihaefugdfy
  • 24-09-2020
  • Chemistry
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Given that the specific heat of chromium is 0.455J/g∙K find the final temperature after 35.9J of energy is removed from 11.7g of chromium at 28.5°C.

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sebassandin
sebassandin sebassandin
  • 02-10-2020

Answer:

[tex]T_2=35.2\°C[/tex]

Explanation:

Hello,

In this case, since the heat is computed in terms of mass, specific heat and temperature as follows:

[tex]Q=mCp(T_2-T_1)[/tex]

In such a way, for the given heat, we obtain the following temperature:

[tex]T_2=T_1+\frac{Q}{mCp}\\ \\T_2=28.5\°C+\frac{35.9J}{11.7g*0.455\frac{J}{g\°C} }\\ \\T_2=35.2\°C[/tex]

Best regards.

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