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  • 23-09-2020
  • Mathematics
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Please solve it Please

Please solve it Please class=

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  • 23-09-2020

Answer:

[tex]\frac{25 \times 5^ \times y^8}{10^3 \times y^5}[/tex] = [tex]\frac{5^{x - 1}y^3 }{8}[/tex]

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