Answer:
163 L CO₂
Explanation:
Step 1: Find conversion
1 mol = 22.4 L at STP
Step 2: Use Dimensional Analysis
[tex]7.29 \hspace{2} mol \hspace{2} CO_2(\frac{22.4 \hspace{2} L \hspace{2} CO_2}{1 \hspace{2} mol \hspace{2} CO_2} )[/tex] = 163.296 L CO₂
Step 3: Simplify
We have 3 sig figs
163.296 L CO₂ ≈ 163 L CO₂
