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A solenoid of 200 turns carrying a current of 2 A has a length of 25 cm. What is the magnitude of the magnetic field at the center of the solenoid?

Respuesta :

Answer:

Explanation:

For magnetic field in a solenoid , the formula is

B = μ₀ n I

Where n is number of turns per unit length and i is current

Putting the values

B = 4π x 10⁻⁷ x (200 / .25) x 2

= 2.00 x 10⁻³ T  

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