Answer:
[tex]\huge\boxed{\cot\dfrac{3\pi}{2}=0}[/tex]
Step-by-step explanation:
[tex]\text{We know}\ \cot x=\cot(x\pm\pi)\ \text{and}\ \cot(-x)=-\cot x.\\\\\text{We have}\ \cot\dfrac{3\pi}{2}=\cot\dfrac{\pi+2\pi}{2}=\cot\bigg(\dfrac{\pi}{2}+\dfrac{2\pi}{2}\bigg)=\cot\bigg(\dfrac{\pi}{2}+\pi\bigg)=\cot\dfrac{\pi}{2}\\\\\cot\bigg(\dfrac{\pi}{2}\bigg)=0\\\\\text{Therefore}\ \cot\dfrac{3\pi}{2}=0.[/tex]
