Answer:
See below
Step-by-step explanation:
The first step is to find the length of AB. By the Pythagorean Theorem:
[tex]AB=\sqrt{26^2-24^2}=\sqrt{676-576}=\sqrt{100}=10[/tex]
Now, you can proceed:
[tex]\sin \theta= \dfrac{24}{26}=\dfrac{12}{13} \\\\\\\cos \theta= \dfrac{10}{26}=\dfrac{5}{13} \\\\\\\tan \theta= \dfrac{24}{10}=\dfrac{12}{5} \\\\\\\csc \theta= \dfrac{13}{12} \\\\\\\sec \theta=\dfrac{13}{5} \\\\\\\cot \theta=\dfrac{5}{12}[/tex]
