tterburgh22
tterburgh22 tterburgh22
  • 26-05-2020
  • Chemistry
contestada

What is the temperature of 4.5 moles of a gas that occupies 50. mL at 1.35 atm?

Respuesta :

Arclight Arclight
  • 31-05-2020

Answer:

[tex]T = 0.182[/tex] Kelvin

Explanation:

As we know that

[tex]PV = nRT\\[/tex]

Where P is the pressure in atmospheric pressure

T is the temperature in Kelvin  

R is the gas constant  

V is the volume in liters

[tex]R = 0.08206[/tex]

Substituting the given values in above equation, we get -

[tex]1.35 * \frac{50}{1000}= 4.5 * 0.08206* T\\[/tex]

On rearranging, we get

[tex]T = \frac{1.35*50}{1000*0.08206*4.5} \\[/tex]

[tex]T = 0.182[/tex] Kelvin

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