Answer: Center is [tex](-\frac{8}{3}, 0)[/tex] and radius is 1.
Step-by-step explanation: The center of a circle [tex](x-a)^{2} + (y-b)^{2} = r^{2}[/tex] is (a,b) & the radius is r. a=[tex]--\frac{8}{3} = \frac{8}{3}[/tex] , b=0, and r=[tex]\sqrt{1}[/tex]=1
