Answer: Center (-2,3), radius 2
Step-by-step explanation: Subtract 9 from both sides, then complete the square for the x and y variables & add to both sides: [tex]x^2+4x+4+y^2-6y+9=-9+4+9[/tex] [tex]= (x+2)^2+(y-3)^2=4[/tex]. The center of this circle in the form [tex](x-a)^2+(y-b)^2=r^2[/tex] is (a,b) with radius r. a=-2, b=3, r=[tex]\sqrt{4}[/tex]=2
