Answer:
b
Step-by-step explanation:
Consider perfect squares on either side of 42, that is
36 < 42 < 49 , thus
[tex]\sqrt{36}[/tex] < [tex]\sqrt{42}[/tex] < [tex]\sqrt{49}[/tex] , that is
6 < [tex]\sqrt{42}[/tex] < 7 → b
Answer: between 6 and 7
Since 6² is 36 and 7² is 49, the square root of 42
would fall somewhere in between these.
Look below.
