Answer:
[tex] (x-3) ^2 +(y-4) ^2 =4[/tex]
Step-by-step explanation:
Center of circle:
[tex] C=(3,\:4) =(h, \:k) \\[/tex]
[tex] Radius \: r = 2[/tex]
Equation of circle in standard form is:
[tex] (x-h) ^2 +(y-k) ^2 =r^2 [/tex]
Substituting the values of h, k and r in above equation, we find:
[tex] (x-3) ^2 +(y-4) ^2 =2^2\\
\purple {\boxed {\bold {(x-3) ^2 +(y-4) ^2 =4}}} \\
[/tex]
