tladitidimatso7591 tladitidimatso7591
  • 23-04-2020
  • Mathematics
contestada

Punkt p (1;2k+1) należy do wykresu funkcji f(x)=-4x2+7. Oblicz k

Respuesta :

AyBaba7 AyBaba7
  • 23-04-2020

Answer:

k = 1

Step-by-step explanation:

English Translation

Find k if the point P (-1, 2k + 1) belongs to the graph of the function f (x) = - 4x^2 + 7.

The function is given as

y = f(x) = -4x² + 7

and point (-1, 2k+1) lies on the graph.

This point means that, at x = -1, y = 2k+1

y = -4x² + 7

Substituting the values in

2k + 1 = -4(-1)² + 7

2k + 1 = -4 + 7 = 3

2k = 3 - 1

2k = 2

k = 1

Hence, the point (-1, 2k+1) is (-1, 3)

To check,

y = -4x² + 7

3 = -4(-1)² + 7

3 = -4 + 7

3 = 3

So, this is truly correct.

Hope this Helps!!!

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