Answer:
233 snakes are heterozygous for the banding allele
Explanation:
According to Hardy-Weinberg, the allelic frequencies in a locus are represented as p and q, referring to the alleles. The genotypic frequencies after one generation are p² (Homozygous for allele p), 2pq (Heterozygous), q² (Homozygous for the allele q). Populations in H-W equilibrium will get the same allelic frequencies generation after generation. The sum of these allelic frequencies equals 1, this is p + q = 1.
In the exposed example,
How many snakes are heterozygous for the banding allele?
The frequency of banded snakes refers to the genotypic frequency for the trait, which is bb= q2= 0.4.
If q2= 0.4, then q = √0.4 = 0.63
The allelic frequency for b is 0.63.
This means that the allelic frequency for B or p is 0.37, which we deduce by clearing the equation p + q = 1
p + 0.63 = 1
p = 1 - 0.63
p = 0.37
The allelic frequency of B is 0,37, and the allelic frequency for b is 0,63. The population heterozygote frequency for this allele is 2 x p x q = 2 x 0,37 x 0,63 = 0.466. The percentage of the population that is heterozygous for this allele is 46%.
As the population size is 500 individuals, then we can calculate how many of these snakes are heterozygous. This is: 0.466 x 500 = 233