michellewilliam michellewilliam
  • 24-07-2016
  • Mathematics
contestada

evaluate the permutation P(36,19)=____

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apologiabiology
apologiabiology apologiabiology
  • 24-07-2016
easy

nPr=[tex] \frac{n!}{(n-r)!} [/tex]
here
36P19=[tex] \frac{36!}{(36-19)!}= [/tex]
[tex] \frac{36!}{(17)!}= [/tex]
[tex] \frac{36*35*34*33*32*31*30*29*28*27*26*25*24*23*22*21*20*19*18}{1}= [/tex]
1045843337171591729971200000





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