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23-07-2016
Mathematics

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-2i (9 − 3i) − (6 − 10i) as a complex number in standard form.

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apologiabiology apologiabiology

23-07-2016

the form is
a+bi
a is the real partt
bi is the imaginary part

add complex parts with complex and real with real

treat 'i' as x
remember, i=√-1 so i^2=-1

-2i(9-3i)-1(6-10i)
distribute
-18i+6i^2-6+10i
-18i-6-6+10i
-18i+10i-6-6
-8i-12
-12-8i

answer is -12-8i

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