kellerpaula kellerpaula

23-03-2020
Mathematics

contestada

Trigonometry
Trigonometric Equations
2 sin x √ 3; x [0,2π]

Respuesta :

amna04352 amna04352

23-03-2020

Answer:

x = π/3, 2π/3

Step-by-step explanation:

2 sin x = √ 3

sin x = √3/2

basic angle = π/3

x = π/3, π - π/3 = 2π/3

x = π/3, 2π/3

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