Answer:
B
Step-by-step explanation:
Consider perfect squares either side of 45, that is
36 < 45 < 49, thus
[tex]\sqrt{36}[/tex] < [tex]\sqrt{45}[/tex] < [tex]\sqrt{49}[/tex], that is
6 < [tex]\sqrt{45}[/tex] < 7
Thus [tex]\sqrt{45}[/tex] is between 6 and 7
Point B lies between 6 and 7
