21-06-2016
Mathematics

contestada

find the derivative of: sqrt( 3x+sqrt( 3x+sqrt( 3x)))

Respuesta :

24-06-2016

Hello,

y'=[tex]( \sqrt{3x+ \sqrt{3x+ \sqrt{3x} } } )'[/tex]

[tex]y'=\dfrac{(3+\frac{1}{2\sqrt{3x+\sqrt{3x}}})*(3+\frac{3}{2\sqrt{3x}})}{2( \sqrt{3x+ \sqrt{3x+ \sqrt{3x} } } )}[/tex]

This make me think of a Ramanuyan 's formula of (x+1)

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