tolmachevnichol
tolmachevnichol tolmachevnichol
  • 26-01-2020
  • Mathematics
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If [tex]\sqrt{x-a} =b[/tex], x > a, what expression is equivalent to x?
A) [tex]b^{2}[/tex] + a
B) [tex]b^{2}[/tex] - a
C) b + a
D) b - a

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PieJee PieJee
  • 26-01-2020

Answer:

A

Step-by-step explanation:

[tex] \sqrt{x - a} = b \\ x - a = b^{2} \\ x = {b}^{2} + a[/tex]

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