Answer:
[tex]f^{-1}(x) = \frac{1}{12}(x+20)[/tex]
Step-by-step explanation:
Given: f(x) = 4(3x - 5)
Is required to find f⁻¹(x)
f(x) = y = 4(3x - 5)
∴ y = 4 * 3x - 4 * 5
∴ y = 12x - 20 ⇒ add 20 to both sides
∴ y + 20 = 12x ⇒ divide both sides by 12
∴ [tex]\frac{1}{12} (y+20) = x[/tex]
Replace the places of x and y.
∴ [tex]y=\frac{1}{12} (x+20)[/tex]
∴ [tex]f^{-1}(x) = \frac{1}{12}(x+20)[/tex]
