Answer:
[tex]\large\boxed{(h\circ g)(x)=6x-16}[/tex]
Step-by-step explanation:
[tex]h(x)=3x-1\\\\g(x)=2x-4\\\\(h\circ g)(x)=h\bigg(g(x)\bigg)\\\\\text{Substitute instead of x the expression (2x - 4) to h (x):}\\\\(h\circ g)(x)=3(2x-4)-4\qquad\text{use the distributive property}\\\\(h\circ g)(x)=(3)(2x)+(3)(-4)-4\\\\(h\circ g)(x)=6x-12-4\\\\(h\circ g)(x)=6x-16[/tex]
