P.E=0.0675 J
Explanation:
Elastic potential Energy=Force × distance of displacement
The formula to apply is;
P.E=1/2 ks²
where k is the spring constant given as; 1.5 *10^-2 N/m and s is the displacement
In this case,
s=3
P.E= 1/2 * 1.5 × 10^-2 ×3²
P.E=1.5×10^-2*4.5
P.E=0.0675 J
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Elastic potential energy:https://brainly.com/question/1352053
Keywords: approximate,value,elastic potential energy,spring, elongated
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