Answer:
Electric flux will be [tex]\Phi =\frac{q}{\epsilon _0}[/tex]
Explanation:
Let the point charge enclosed by Gaussian surface is q
We have to find the electric flux through this Gaussian surface
According to Gauss law electric flux through any closed surface is equal to [tex]\frac{1}{\epsilon _0}[/tex] times of charged enclosed by the surface.
So electric flux will be [tex]\Phi =\frac{q}{\epsilon _0}[/tex]
Gauss law is only valid for closed surface it is not applied for open surface
