Answer:
3462.3N
Explanation:
3000 lbs = 3000 / 2.2 = 1363.6kg
Let g = 9.81 m/s2. The weight of the car is
W = mg = 1363.6*9.81 = 13377 N
Since the car is parked on a hill that makes an angle of 15 degrees with the horizontal, the gravity force that is parallel with the road is
Wsin(15) = 13377*0.2588 = 3462.3 N
Which is also the force that is required to keep the 3000lb car stationary.
