Answer:
V = 33.62 L
Explanation:
Given data:
Volume = ?
Number of moles of oxygen = 1.5 mol
Temperature = 273 K
Pressure = 1 atm
Solution:
Standard pressure = 1 atm
Standard temperature = 273 K
PV = nRT
V = nRT/ P
V = 1.5 mol × 0.0821 atm. L. K⁻¹. mol⁻¹ × 273 k / 1 atm
V = 33.62 L. atm// 1 atm
V = 33.62 L
