Answer:
a) x (x-9) (x+3)
b) x (x+4)(x-4)
c) (x)(x)(x + 16)
Step-by-step explanation:
We're going to equal the functions to zero and find their roots by factorizing:
a) f(x)=x³-6x²-27x
x³-6x²-27x = 0
x(x²-6x-27) = 0
⇒x (x-9) (x+3)
b) f(x)=x³-16x
x³-16x = 0
x (x²-16) =0
⇒x (x+4)(x-4)
c) f(x)=x³+16x²
x³ + 16x² = 0
x² ( x +16)
⇒(x)(x)(x + 16)
