Answer:
Step-by-step explanation:
Given
[tex]\left ( k+1\right )x^2+4kx+2=0[/tex]
For Discriminant of ax^2+bx+c=0
[tex]D=\sqrt{b^2-4ac}[/tex]
here
[tex]D=\sqrt{\left ( 4k\right )^2-4\left ( k+1\right )\left ( 2\right )}[/tex]
[tex]D=\sqrt{16k^2-8k-8}>0[/tex] for real roots
so [tex]16k^2-8k-8>0[/tex]
[tex]2k^2-k-1>0[/tex] is a form of Quadratic equation
