Respuesta :

MathPhys

Answer:

44.1 m

Explanation:

Given:

v₀ = 0 m/s

a = -9.8 m/s²

t = 3 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (3 s) + ½ (-9.8 m/s²) (3 s)²

Δy = -44.1 m

The ball should be dropped from 44.1 meters.

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