Answer:
x = 3
Step-by-step explanation:
[tex]\left \{ {{6x-5y=8} \atop {2x+9y=24}} \right.[/tex]
I'm going to use the method of elimination by multiplying the second equation by -3:
[tex]\left \{ {{6x-5y=8} \atop {-6x-27y=-72}} \right.[/tex]
Then I can eliminate x:
-32y = -64
To solve for y, I'd simply divide:
y = 2
Because I now have y = 2, I'll just plug in 2:
6x - 5(2) = 8
6x - 10 = 8
6x = 18
x = 3
Hopefully I helped :)
