Answer:
[tex]x_{1} = -4\\\\x_{2} = 8[/tex]
Step-by-step explanation:
6(8-x)(x+4)=0
(48 -6x )(x+4) = 0
48x +192 -6x^2 -24x = 0
6x^2 -24x -192=0
using quadratic formula:
[tex]x =\frac{-b+-\sqrt{b^{2}-4*a*c}}{2*a}[/tex]
a= 6 b= -24 c= -192
we have:
[tex]x_{1} = -4\\\\x_{2} = 8[/tex]
