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A 35 kg crate undergoes a horizontal acceleration of 1.5 m/s^2 on a level surface when pulled by a 65.0 N force. What is the coefficient of kinetic friction between the crate and the surface?

Respuesta :

Answer:

μ = 0.036

Explanation:

m = 35 kg

a = 1.5 m/s^2

Force applied, F = 65 N

Let f be the friction force.

net force = F - f

According to Newton's second law

F - f = m x a

65 - f = 35 x 1.5

65 - f = 52.5

f = 65 - 52.5 = 12.5 N

Now by the law of friction

f = μ m g

where, μ is the coefficient of friction

12.5 = μ x 35 x 9.8

μ = 0.036

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