Answer:
[tex]\boxed{9.68(1409)^{x}}[/tex]
Explanation:
log y = 0.986 + 3.149x
Take the antilogarithm of each side
[tex]\begin{array}{rcl}10^{\log y} & = & 10^{0.986 + 3.149x}\\y & = & 10^{0.986} \times 10^{3.149x} \\& = & 9.68 \times 10^{3.149x}\\& = & 9.68 \times \left(10^{3.149} \right )^{x}\\& = & \mathbf{9.68(1409)^{x}}\\\end{array}\\\text{The exponential form of the regression is } \boxed{\mathbf{9.68(1409)^{x}}}[/tex]
