taylorgallien34291 taylorgallien34291
  • 21-08-2019
  • Physics
contestada

A 460 nm monochromatic light is split into two beams. The two beams arrive at a point on a screen with a path difference of 920nm. Calculate the phase difference.

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rejkjavik rejkjavik
  • 22-08-2019

Answer:

phase difference [tex]\Delta \Phi = 12.566[/tex]

Explanation:

Phase difference is expressed as [tex]\Delta \Phi[/tex]

[tex]\Delta \Phi =\frac {2\pi}{\lambda} \Delta X[/tex]

Where,

[tex]\Delta \Phi[/tex]= phase difference

[tex]\lambda[/tex]  wavelength = 460nm

[tex]\Delta X[/tex]  path difference = 920 nm

[tex]\Delta \Phi =\frac {2\pi}{460} *920 = 4\pi[/tex]

therefore

phase difference [tex]\Delta \Phi = 12.566[/tex]

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