Answer:
0.0466
Step-by-step explanation:
For a random variable X which follows a binomial distribution:
[tex]n = 7\\p = 0.35[/tex]
Thus,
[tex]P(X=5)={7\choose5}(0.35)^5(1-0.35)^{7-5}\\P(X=5)={7\choose5}(0.35)^5(0.65)^{2}\\P(X=5)=0.0466[/tex]
