mia370 mia370
  • 26-05-2019
  • Mathematics
contestada

What is the first four terms of 3n²

Respuesta :

r3t40
r3t40 r3t40
  • 26-05-2019

Suppose there is a function [tex]f(n)=3n^2, n\in\mathbb{N}[/tex].

We start counting by 1 from the first element in domain of natural numbers so: 1, 2, 3, 4.

We assemble the definition set [tex]A=\{1,2,3,4\}[/tex] than use the function f(n) to create transformation set:

[tex]f(A)=3\{1,2,3,4\}^2\Longrightarrow\{3,6,9,12\}^2 \\

\boxed{B=\{9,36,81,144\}}

[/tex]

So the first four terms are defined in transformation set B.

Hope this helps.

r3t40

Answer Link

Otras preguntas

What are the unit rates for  4/8 , 5/25, 36/6, 14/21, 18/30, 28/16, 56/35, 45/108, 12/42, 39/26
-2n-h(4rx-6s)-3rx+3s i need help doing this problem
Juan is thinking of two numbers. He says that 3 times the first number minus the second number is 118. In addition, two times the first number plus the second n
what are some examples of figurative language found in the book Divergent?
-2n-h(4rx-6s)-3rx+3s i need help doing this problem
what are some examples of figurative language found in the book Divergent?
factor: 6x+36=  how do I solve this problem
Juan is thinking of two numbers. He says that 3 times the first number minus the second number is 118. In addition, two times the first number plus the second n
What are the unit rates for  4/8 , 5/25, 36/6, 14/21, 18/30, 28/16, 56/35, 45/108, 12/42, 39/26
What particles make up the nucleus of an atom?